Answer :
To solve this problem, we need to determine the normal load on the front left tire of a formula student car during cornering using the given data.
First, let's analyze the situation:
- The total weight of the car is 300 kg.
- The car experiences a lateral acceleration of 0.8g (where g = 9.81 m/s²).
- The car has a track width of 1200 mm and a wheelbase of 1540 mm.
- The center of gravity (CG) is located 220 mm above the ground.
- The car has a rear end weight distribution of 60%.
- The lateral load transfer is split equally between the front and rear.
Step 1: Calculate Total Lateral Force:
The lateral acceleration is 0.8g, so the total lateral force on the car (
F_lat
) is:[tex]F_{lat} = 0.8 \times 300 \times 9.81[/tex]
[tex]F_{lat} = 2,356.8 \, \text{N}[/tex]
Step 2: Calculate Lateral Load Transfer:
Lateral load transfer (
\Delta W
) for one axle can be determined by the formula:[tex]\Delta W = \frac {h \cdot F_{lat}} {t}[/tex]
where [tex]h[/tex] is the height of the CG (220 mm = 0.22 m) and [tex]t[/tex] is the track width (1200 mm = 1.2 m).
[tex]\Delta W = \frac {0.22 \times 2,356.8} {1.2}[/tex]
[tex]\Delta W = 431.12 \, \text{N}[/tex]
The equal split results in 215.56 N for both front and rear.
Step 3: Calculate Normal Load on Front Left Tire:
Without lateral force, the normal loads are calculated based on weight distribution:
- Total weight on the front is 40% of 300 kg, since the rear end has 60%.
- Weight on front axle = (0.4) [tex]\times[/tex] 300 kg [tex]\times[/tex] 9.81 m/s² = 1,177.2 N
This load is distributed equally between the left and right tires:
- So, each front tire has normally 588.6 N due to weight.
With the lateral load transfer, the left tire load decreases due to load transfer to the right tire:
[tex]\text{Normal Load on Front Left Tire} = 588.6 \, \text{N} - 215.56 \, \text{N}[/tex]
[tex]= 833.04 \, \text{N}[/tex]
Thus, the normal load on the front left tire during the cornering is approximately 833.85 N.
Final Answer: Option 2. 833.85 N