A candy company has 141 kg of chocolate covered nuts and 81 kg of chocolate-covered raisins to be sold as two different mixes One me will contain half nuts and halt raisins and will sel for $7 pet kg. The other mix will contun nuts and raisins and will sell ter so 50 per kg. Complete parts a, and b. 4 (a) How many kilograms of each mix should the company prepare for the maximum revenue? Find the maximum revenue The company should preparo kg of the test mix and kg of the second mix for a maximum revenue of s| (b) The company raises the price of the second mix to $11 per kg Now how many klograms of each ma should the company propare for the muomum revenue? Find the maximum revenue The company should prepare kg of the first mix and I kg of the second mix for a maximum revenue of

Let x be the number of kilograms of the first mix (half nuts and half raisins) that the company produces. Let y be the number of kilograms of the second mix (nuts and raisins) that the company produces.

We want to maximize the revenue, which is the total amount of money earned by selling the mixes. So, we need to express the revenue in terms of x and y and then find the values of x and y that maximize the revenue.

Step 1: Rewrite the revenue function

The revenue from selling the first mix is still 7x dollars, but the revenue from selling the second mix is now 11y dollars (since it sells for $11 per kg).

Therefore, the total revenue is R = 7x + 11y dollars.

Step 2: Rewrite the constraints

The constraints are still the same: x/2 + y/2 ≤ 141 and x/2 + y/2 ≤ 81.

Step 3: Draw the feasible region

The feasible region is still the same, so we can use the same graph:Graph of the feasible region for the chocolate mix problem

Step 4: Find the corner points of the feasible region

The corner points are still the same: (0, 81), (141, 0), and (54, 54).

Step 5: Evaluate the revenue function at the corner points

Corner point (0, 81): R = 7x + 11y = 7(0) + 11(81) = 891

Corner point (141, 0): R = 7x + 11y = 7(141) + 11(0) = 987

Corner point (54, 54): R = 7x + 11y = 7(54) + 11(54) = 756

The maximum revenue is $987, and it still occurs when the company produces 141 kg of the second mix and 0 kg of the first mix.

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