High School

If an object is dropped from a height of 141 feet, the function [tex]h(t) = -16t^2 + 141[/tex] gives the height of the object after [tex]t[/tex] seconds. When will the object hit the ground?

Answer :

Answer:

Therefore the object will hit the ground after 3 seconds.

Step-by-step explanation:

Given that an object is dropped from a height of 141 feet.

Given function is

h(t)= - 16t²+141

When the object hits the ground, the height of the object will be zero.

It means h(t) = 0

Putting the h(t)=0 in the given function

0 = - 16t²+141

⇒-16t²+144=0

⇒ -16t² = -144

⇒16t²=144

[tex]\Rightarrow t^2 =\frac{144}{16}[/tex]

Square rooting both sides

[tex]\Rightarrow t=\sqrt{\frac{144}{16}}[/tex]

[tex]\Rightarrow t= \frac{12}{4}[/tex]

⇒t = 3

Therefore the object will hit the ground after 3 seconds.