Answer :
We start with the observation that
[tex]$$
133 = 137 - 4 \quad \text{and} \quad 141 = 137 + 4.
$$[/tex]
This suggests using the difference of squares formula, which states that for any numbers [tex]$a$[/tex] and [tex]$b$[/tex],
[tex]$$
(a-b)(a+b) = a^2 - b^2.
$$[/tex]
Here, let [tex]$a = 137$[/tex] and [tex]$b = 4$[/tex]. Then,
[tex]$$
133 \times 141 = (137-4)(137+4) = 137^2 - 4^2.
$$[/tex]
We are given that:
[tex]$$
137^2 = 18769.
$$[/tex]
And we calculate:
[tex]$$
4^2 = 16.
$$[/tex]
Substitute these values into the expression:
[tex]$$
133 \times 141 = 18769 - 16 = 18753.
$$[/tex]
Thus, the value of [tex]$133 \times 141$[/tex] is [tex]$\boxed{18753}$[/tex].
[tex]$$
133 = 137 - 4 \quad \text{and} \quad 141 = 137 + 4.
$$[/tex]
This suggests using the difference of squares formula, which states that for any numbers [tex]$a$[/tex] and [tex]$b$[/tex],
[tex]$$
(a-b)(a+b) = a^2 - b^2.
$$[/tex]
Here, let [tex]$a = 137$[/tex] and [tex]$b = 4$[/tex]. Then,
[tex]$$
133 \times 141 = (137-4)(137+4) = 137^2 - 4^2.
$$[/tex]
We are given that:
[tex]$$
137^2 = 18769.
$$[/tex]
And we calculate:
[tex]$$
4^2 = 16.
$$[/tex]
Substitute these values into the expression:
[tex]$$
133 \times 141 = 18769 - 16 = 18753.
$$[/tex]
Thus, the value of [tex]$133 \times 141$[/tex] is [tex]$\boxed{18753}$[/tex].
