Answer :
We are given the function
[tex]$$
f(x) = \sqrt{2x - 9}.
$$[/tex]
To find [tex]$f(29)$[/tex], follow these steps:
1. Substitute [tex]$x = 29$[/tex] into the expression inside the square root:
[tex]$$
2(29) - 9.
$$[/tex]
2. Compute the expression:
[tex]$$
2 \times 29 = 58,
$$[/tex]
so
[tex]$$
58 - 9 = 49.
$$[/tex]
3. Now, the function becomes:
[tex]$$
f(29) = \sqrt{49}.
$$[/tex]
4. Calculate the square root:
[tex]$$
\sqrt{49} = 7.
$$[/tex]
5. Since the result is [tex]$7$[/tex], and rounding to the nearest tenth gives [tex]$7.0$[/tex], the final answer is:
[tex]$$
\boxed{7.0}.
$$[/tex]
[tex]$$
f(x) = \sqrt{2x - 9}.
$$[/tex]
To find [tex]$f(29)$[/tex], follow these steps:
1. Substitute [tex]$x = 29$[/tex] into the expression inside the square root:
[tex]$$
2(29) - 9.
$$[/tex]
2. Compute the expression:
[tex]$$
2 \times 29 = 58,
$$[/tex]
so
[tex]$$
58 - 9 = 49.
$$[/tex]
3. Now, the function becomes:
[tex]$$
f(29) = \sqrt{49}.
$$[/tex]
4. Calculate the square root:
[tex]$$
\sqrt{49} = 7.
$$[/tex]
5. Since the result is [tex]$7$[/tex], and rounding to the nearest tenth gives [tex]$7.0$[/tex], the final answer is:
[tex]$$
\boxed{7.0}.
$$[/tex]
