Answer :
We start with the equation
[tex]$$7x^2 = 343.$$[/tex]
1. Divide both sides of the equation by [tex]$7$[/tex] to isolate [tex]$x^2$[/tex]:
[tex]$$x^2 = \frac{343}{7} = 49.$$[/tex]
2. To solve for [tex]$x$[/tex], take the square root of both sides. Remember that the square root of a number has both a positive and negative value:
[tex]$$x = \pm\sqrt{49}.$$[/tex]
3. Since [tex]$\sqrt{49} = 7$[/tex], the solutions are
[tex]$$x = 7 \quad \text{and} \quad x = -7.$$[/tex]
Thus, the solutions to the equation are [tex]$-7$[/tex] and [tex]$7$[/tex].
[tex]$$7x^2 = 343.$$[/tex]
1. Divide both sides of the equation by [tex]$7$[/tex] to isolate [tex]$x^2$[/tex]:
[tex]$$x^2 = \frac{343}{7} = 49.$$[/tex]
2. To solve for [tex]$x$[/tex], take the square root of both sides. Remember that the square root of a number has both a positive and negative value:
[tex]$$x = \pm\sqrt{49}.$$[/tex]
3. Since [tex]$\sqrt{49} = 7$[/tex], the solutions are
[tex]$$x = 7 \quad \text{and} \quad x = -7.$$[/tex]
Thus, the solutions to the equation are [tex]$-7$[/tex] and [tex]$7$[/tex].
