The means and mean absolute deviations of the individual times of members on two [tex]4 \times 400[/tex]-meter relay track teams are shown in the table below.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{\text{Means and Mean Absolute Deviations of Individual Times of Members of } [4 \times 400] \text{-meter Relay Track Teams}} \\
\hline
& \text{Team A} & \text{Team B} \\
\hline
\text{Mean} & 59.32 \, \text{s} & 59.1 \, \text{s} \\
\hline
\text{Mean Absolute Deviation} & 1.5 \, \text{s} & 1.5 \, \text{s} \\
\hline
\end{array}
\]
[/tex]

What is the ratio of the difference in the means of the two teams to the mean absolute deviation of Team B?

A. 0.09
B. 0.15
C. 0.25
D. 0.65

Sure! Let's solve this problem step-by-step:

1. Identify the Information Given:
- Mean time for Team A: 59.32 seconds
- Mean time for Team B: 59.1 seconds
- Mean absolute deviation (MAD) for Team B: 1.5 seconds

2. Calculate the Difference in the Means of the Two Teams:
To find out the difference in the mean times between the two teams, subtract the mean of Team B from the mean of Team A:
[tex]\[
\text{Difference in means} = \text{Mean of Team A} - \text{Mean of Team B}
\][/tex]
So,
[tex]\[
\text{Difference in means} = 59.32 - 59.1 = 0.22 \text{ seconds}
\][/tex]

3. Determine the Ratio:
We need to find the ratio of this difference in the means to the mean absolute deviation of Team B. The formula for the ratio is:
[tex]\[
\text{Ratio} = \frac{\text{Difference in means}}{\text{MAD of Team B}}
\][/tex]
Thus,
[tex]\[
\text{Ratio} = \frac{0.22}{1.5} \approx 0.15
\][/tex]

4. Select the Closest Answer:
Given the options, the closest answer to the calculated ratio of approximately 0.15 is indeed 0.15.

Therefore, the correct answer is 0.15.