Answer :
To solve the division problem [tex]\(1564 \div 234\)[/tex], we'll calculate the quotient and the remainder.
1. Divide: Start by dividing 1564 by 234. You need to find how many whole times 234 can fit into 1564.
2. Estimate: First, estimate the nearest number of times you can multiply 234 to approach 1564. By trying different multiples, you'll discover that 234 can go into 1564 six times without exceeding it.
3. Calculate: Multiply 234 by 6. This gives us [tex]\(234 \times 6 = 1404\)[/tex].
4. Subtract: Subtract 1404 from 1564 to find the remainder.
[tex]\[
1564 - 1404 = 160
\][/tex]
5. Conclusion: So, 1564 divided by 234 is 6 with a remainder of 160.
The quotient is 6, and the remainder is 160. Therefore, the answer is:
A. [tex]\(6 \, r \, 160\)[/tex]
1. Divide: Start by dividing 1564 by 234. You need to find how many whole times 234 can fit into 1564.
2. Estimate: First, estimate the nearest number of times you can multiply 234 to approach 1564. By trying different multiples, you'll discover that 234 can go into 1564 six times without exceeding it.
3. Calculate: Multiply 234 by 6. This gives us [tex]\(234 \times 6 = 1404\)[/tex].
4. Subtract: Subtract 1404 from 1564 to find the remainder.
[tex]\[
1564 - 1404 = 160
\][/tex]
5. Conclusion: So, 1564 divided by 234 is 6 with a remainder of 160.
The quotient is 6, and the remainder is 160. Therefore, the answer is:
A. [tex]\(6 \, r \, 160\)[/tex]
