Answer :
To find the mean, median, and midrange of the scores, we follow these steps:
1. Mean:
- First, we add up all the scores: [tex]\( 68 + 62 + 60 + 64 + 70 + 66 + 72 = 462 \)[/tex].
- Then, we divide the total by the number of scores: [tex]\( \frac{462}{7} = 66 \)[/tex].
- So, the mean is 66.
2. Median:
- To find the median, we first need to sort the scores in ascending order: 60, 62, 64, 66, 68, 70, 72.
- Since there are seven scores, which is an odd number, the median is the middle score.
- The middle score (fourth one in our sorted list) is 66.
- Therefore, the median is 66.
3. Midrange:
- The midrange is found by taking the average of the smallest and largest scores.
- The smallest score is 60, and the largest score is 72.
- We calculate [tex]\( \frac{60 + 72}{2} = \frac{132}{2} = 66 \)[/tex].
- So, the midrange is 66.
Given these calculations, the correct answer is:
d. Mean [tex]\(=66\)[/tex], median [tex]\(=66\)[/tex], midrange [tex]\(=66\)[/tex]
1. Mean:
- First, we add up all the scores: [tex]\( 68 + 62 + 60 + 64 + 70 + 66 + 72 = 462 \)[/tex].
- Then, we divide the total by the number of scores: [tex]\( \frac{462}{7} = 66 \)[/tex].
- So, the mean is 66.
2. Median:
- To find the median, we first need to sort the scores in ascending order: 60, 62, 64, 66, 68, 70, 72.
- Since there are seven scores, which is an odd number, the median is the middle score.
- The middle score (fourth one in our sorted list) is 66.
- Therefore, the median is 66.
3. Midrange:
- The midrange is found by taking the average of the smallest and largest scores.
- The smallest score is 60, and the largest score is 72.
- We calculate [tex]\( \frac{60 + 72}{2} = \frac{132}{2} = 66 \)[/tex].
- So, the midrange is 66.
Given these calculations, the correct answer is:
d. Mean [tex]\(=66\)[/tex], median [tex]\(=66\)[/tex], midrange [tex]\(=66\)[/tex]
