High School

The quotient of [tex]\left(x^4 + 5x^3 - 3x - 15\right)[/tex] and [tex]\left(x^3 - 3\right)[/tex] is a polynomial.

Which of the following is the quotient?

A. [tex]x^7 + 5x^6 - 6x^4 - 30x^3 + 9x + 45[/tex]

B. [tex]x - 5[/tex]

C. [tex]x + 5[/tex]

D. [tex]x^7 + 5x^6 + 6x^4 + 30x^3 + 9x + 45[/tex]

Answer :

To find the quotient of the polynomial [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] divided by [tex]\((x^3 - 3)\)[/tex], we need to perform polynomial long division. Here's a step-by-step explanation of how this is done:

1. Set Up the Division:
- The dividend (numerator) is [tex]\(x^4 + 5x^3 - 3x - 15\)[/tex].
- The divisor (denominator) is [tex]\(x^3 - 3\)[/tex].

2. Divide the Leading Terms:
- Divide the leading term of the dividend, [tex]\(x^4\)[/tex], by the leading term of the divisor, [tex]\(x^3\)[/tex].
- This gives the first term of the quotient: [tex]\(x^4 \div x^3 = x\)[/tex].

3. Multiply and Subtract:
- Multiply the entire divisor [tex]\(x^3 - 3\)[/tex] by this first quotient term [tex]\(x\)[/tex], which results in [tex]\(x \cdot (x^3 - 3) = x^4 - 3x\)[/tex].
- Subtract this result from the original dividend. This yields:
[tex]\[
(x^4 + 5x^3 - 3x - 15) - (x^4 - 3x) = 5x^3 + 0x^2
\][/tex]

4. Repeat the Process:
- Now take the new polynomial [tex]\(5x^3 + 0x^2\)[/tex] and repeat the division process. Divide the leading term, [tex]\(5x^3\)[/tex], by [tex]\(x^3\)[/tex], yielding [tex]\(5\)[/tex].
- Multiply the divisor by [tex]\(5\)[/tex] to get [tex]\(5 \cdot (x^3 - 3) = 5x^3 - 15\)[/tex].
- Subtract this result from the current dividend:
[tex]\[
(5x^3 + 0x^2) - (5x^3 - 15) = 15
\][/tex]

5. Remainder:
- After subtraction, we are left with [tex]\(15\)[/tex], which is a constant and the remainder.
- Since we are only interested in the quotient, and the problem specifies that the quotient is a polynomial, we stop here.

6. Result:
- Therefore, the quotient of [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] divided by [tex]\((x^3 - 3)\)[/tex] is [tex]\(x + 5\)[/tex].

So, the polynomial that represents the quotient is [tex]\(x + 5\)[/tex].

Other Questions