College

A number, [tex]n[/tex], is added to 15 less than 3 times itself. The result is 101. Which equation can be used to find the value of [tex]n[/tex]?

A. [tex]3n - 15 + n = 101[/tex]
B. [tex]3n + 15 + n = 101[/tex]
C. [tex]3n - 15 - n = 101[/tex]
D. [tex]3n + 15 - n = 101[/tex]

Answer :

To solve the problem, let's break it down step by step:

1. Understanding the expression:

We need to express the statement in the problem as an equation. The statement says a number, [tex]\( n \)[/tex], is added to 15 less than 3 times itself. Let's represent this in algebraic terms:

- "3 times itself" is [tex]\( 3n \)[/tex].
- "15 less than 3 times itself" is [tex]\( 3n - 15 \)[/tex].

2. Setting up the equation:

The problem says this result when added to [tex]\( n \)[/tex] equals 101. So, we set up the equation:

[tex]\[
n + (3n - 15) = 101
\][/tex]

3. Simplifying the equation:

Now, let's simplify it:

- Combine the [tex]\( n \)[/tex] terms: [tex]\( n + 3n = 4n \)[/tex]

So the equation becomes:

[tex]\[
4n - 15 = 101
\][/tex]

4. Identifying the correct equation:

The equation we derived from the problem statement is the one where [tex]\( n \)[/tex] is added to 15 less than 3 times itself, which simplifies to:

[tex]\[
3n - 15 + n = 101
\][/tex]

Therefore, the correct choice among the given options is:

[tex]\[
3n - 15 + n = 101
\][/tex]

The chosen equation reflects the logic described in the problem.