High School

The quotient of [tex]\left(x^4+5x^3-3x-15\right)[/tex] and [tex]\left(x^3-3\right)[/tex] is a polynomial. What is the quotient?

A. [tex]x^7+5x^6-6x^4-30x^3+9x+45[/tex]

B. [tex]x-5[/tex]

C. [tex]x+5[/tex]

D. [tex]x^7+5x^6+6x^4+30x^3+9x+45[/tex]

Answer :

Let's find the quotient of the polynomial [tex]\( x^4 + 5x^3 - 3x - 15 \)[/tex] divided by [tex]\( x^3 - 3 \)[/tex].

We'll use polynomial long division:

1. Divide the first term of the dividend by the first term of the divisor:
[tex]\[
\frac{x^4}{x^3} = x
\][/tex]
So, the first term of the quotient is [tex]\( x \)[/tex].

2. Multiply the entire divisor by this term:
[tex]\[
x \times (x^3 - 3) = x^4 - 3x
\][/tex]

3. Subtract this from the original polynomial:
[tex]\[
(x^4 + 5x^3 - 3x - 15) - (x^4 - 3x) = 5x^3 + 0x^2 - 3x + 0 - (-3x) \Rightarrow 5x^3 - 15
\][/tex]

4. Repeat the process with the new polynomial:
- [tex]\( \frac{5x^3}{x^3} = 5 \)[/tex]
- So, our quotient becomes [tex]\( x + 5 \)[/tex].

5. Multiply the entire divisor by this new term:
[tex]\[
5 \times (x^3 - 3) = 5x^3 - 15
\][/tex]

6. Subtract this from the current polynomial:
[tex]\[
(5x^3 - 15) - (5x^3 - 15) = 0
\][/tex]

Since we're left with a remainder of zero, the quotient of [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] divided by [tex]\((x^3 - 3)\)[/tex] is simply:

[tex]\( x + 5 \)[/tex].

So, the answer is: [tex]\( x + 5 \)[/tex].