College

Convert the following temperatures to Celsius:

6) [tex]$32^{\circ} F$[/tex]

7) [tex]$45^{\circ} F$[/tex]

8) [tex]$70^{\circ} F$[/tex]

9) [tex]$80^{\circ} F$[/tex]

10) [tex]$90^{\circ} F$[/tex]

11) [tex]$212^{\circ} F$[/tex]

Answer :

Certainly! Let's convert each given temperature from Fahrenheit to Celsius using the standard conversion formula:

The formula to convert Fahrenheit (°F) to Celsius (°C) is:

[tex]\[ C = \frac{5}{9} \times (F - 32) \][/tex]

Now, let's apply this formula to each temperature:

1. [tex]$32^\circ F$[/tex] to Celsius:

[tex]\[ C = \frac{5}{9} \times (32 - 32) = \frac{5}{9} \times 0 = 0.0^\circ C \][/tex]

2. [tex]$45^\circ F$[/tex] to Celsius:

[tex]\[ C = \frac{5}{9} \times (45 - 32) = \frac{5}{9} \times 13 \approx 7.22^\circ C \][/tex]

3. [tex]$70^\circ F$[/tex] to Celsius:

[tex]\[ C = \frac{5}{9} \times (70 - 32) = \frac{5}{9} \times 38 \approx 21.11^\circ C \][/tex]

4. [tex]$80^\circ F$[/tex] to Celsius:

[tex]\[ C = \frac{5}{9} \times (80 - 32) = \frac{5}{9} \times 48 \approx 26.67^\circ C \][/tex]

5. [tex]$90^\circ F$[/tex] to Celsius:

[tex]\[ C = \frac{5}{9} \times (90 - 32) = \frac{5}{9} \times 58 \approx 32.22^\circ C \][/tex]

6. [tex]$212^\circ F$[/tex] to Celsius:

[tex]\[ C = \frac{5}{9} \times (212 - 32) = \frac{5}{9} \times 180 = 100.0^\circ C \][/tex]

These calculations give us the following Celsius temperatures:

- [tex]$32^\circ F$[/tex] = [tex]$0.0^\circ C$[/tex]
- [tex]$45^\circ F$[/tex] = [tex]$7.22^\circ C$[/tex]
- [tex]$70^\circ F$[/tex] = [tex]$21.11^\circ C$[/tex]
- [tex]$80^\circ F$[/tex] = [tex]$26.67^\circ C$[/tex]
- [tex]$90^\circ F$[/tex] = [tex]$32.22^\circ C$[/tex]
- [tex]$212^\circ F$[/tex] = [tex]$100.0^\circ C$[/tex]

And there you go, those are the conversions from Fahrenheit to Celsius!