Answer :
Sure! Let's convert each of the given Fahrenheit temperatures to Celsius using the conversion formula:
The formula to convert Fahrenheit to Celsius is:
[tex]\[ \text{Celsius} = (\text{Fahrenheit} - 32) \times \frac{5}{9} \][/tex]
Now, let's apply this formula to each temperature:
1. Convert [tex]\(32^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (32 - 32) \times \frac{5}{9} = 0.0^\circ C
\][/tex]
2. Convert [tex]\(45^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (45 - 32) \times \frac{5}{9} \approx 7.22^\circ C
\][/tex]
3. Convert [tex]\(70^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (70 - 32) \times \frac{5}{9} \approx 21.11^\circ C
\][/tex]
4. Convert [tex]\(80^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (80 - 32) \times \frac{5}{9} \approx 26.67^\circ C
\][/tex]
5. Convert [tex]\(212^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (212 - 32) \times \frac{5}{9} = 100.0^\circ C
\][/tex]
So, the conversions are as follows:
- [tex]\(32^\circ F\)[/tex] is [tex]\(0.0^\circ C\)[/tex]
- [tex]\(45^\circ F\)[/tex] is approximately [tex]\(7.22^\circ C\)[/tex]
- [tex]\(70^\circ F\)[/tex] is approximately [tex]\(21.11^\circ C\)[/tex]
- [tex]\(80^\circ F\)[/tex] is approximately [tex]\(26.67^\circ C\)[/tex]
- [tex]\(212^\circ F\)[/tex] is [tex]\(100.0^\circ C\)[/tex]
The formula to convert Fahrenheit to Celsius is:
[tex]\[ \text{Celsius} = (\text{Fahrenheit} - 32) \times \frac{5}{9} \][/tex]
Now, let's apply this formula to each temperature:
1. Convert [tex]\(32^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (32 - 32) \times \frac{5}{9} = 0.0^\circ C
\][/tex]
2. Convert [tex]\(45^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (45 - 32) \times \frac{5}{9} \approx 7.22^\circ C
\][/tex]
3. Convert [tex]\(70^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (70 - 32) \times \frac{5}{9} \approx 21.11^\circ C
\][/tex]
4. Convert [tex]\(80^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (80 - 32) \times \frac{5}{9} \approx 26.67^\circ C
\][/tex]
5. Convert [tex]\(212^\circ F\)[/tex] to Celsius:
[tex]\[
\text{Celsius} = (212 - 32) \times \frac{5}{9} = 100.0^\circ C
\][/tex]
So, the conversions are as follows:
- [tex]\(32^\circ F\)[/tex] is [tex]\(0.0^\circ C\)[/tex]
- [tex]\(45^\circ F\)[/tex] is approximately [tex]\(7.22^\circ C\)[/tex]
- [tex]\(70^\circ F\)[/tex] is approximately [tex]\(21.11^\circ C\)[/tex]
- [tex]\(80^\circ F\)[/tex] is approximately [tex]\(26.67^\circ C\)[/tex]
- [tex]\(212^\circ F\)[/tex] is [tex]\(100.0^\circ C\)[/tex]
