High School

What must be the value of x so that lines a and b are parallel lines cut by transversal f?




The value of x is ? i thought it was 84 but thats wrong

What must be the value of x so that lines a and b are parallel lines cut by transversal f The value of x is

Answer :

we know that

if the lines a and b are parallel lines cut by transversal f

then

[tex](6x-36)=96[/tex] --------> by alternate exterior angles

solve for x

[tex](6x-36)=96\\ 6x=96+36\\6x=132\\x=(132/6)\\x=22\ degrees[/tex]

therefore

the answer is

the value of x is [tex]22\ degrees[/tex]
the answer is 22 i did it on ed
and i got it correct

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