Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to understand the relationship between atomic mass, moles, and Avogadro's number.
1. Understanding Atomic Mass:
- The atomic mass of potassium is given as 39.1. This means that one mole of potassium atoms has a mass of 39.1 grams.
2. Understanding Avogadro's Number:
- Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms in one mole of any element.
3. Calculation:
- Since the problem asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, and we know that this is precisely one mole of potassium atoms, we simply need to use the atomic mass of potassium to find the total mass.
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] (one mole) of potassium atoms is 39.1 grams.
Thus, the correct answer is:
B. [tex]\(39.1 \text{ g}\)[/tex]
1. Understanding Atomic Mass:
- The atomic mass of potassium is given as 39.1. This means that one mole of potassium atoms has a mass of 39.1 grams.
2. Understanding Avogadro's Number:
- Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms in one mole of any element.
3. Calculation:
- Since the problem asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, and we know that this is precisely one mole of potassium atoms, we simply need to use the atomic mass of potassium to find the total mass.
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] (one mole) of potassium atoms is 39.1 grams.
Thus, the correct answer is:
B. [tex]\(39.1 \text{ g}\)[/tex]
