Answer :
Answer:
Total volume of gaseous products = 882.9 L
Explanation:
The balanced equation for combustion of butane is:
[tex]C_4H_{10}+\frac{13}{2} O_{2}\ --->\ 4CO_{2}+5H_2O[/tex]
At constant temperature and pressure volume of gas is directly proportional to number of moles of the gas.
Then from the balanced equation we can say that:
1 L of butane reacts with 6.5 L of oxygen to give 4 L of carbon dioxide and 5 L of water.
98.1 L of butane gives 4*98.1 L of carbon dioxide and 5*98.1 L of water.
Hence total volume of gaseous products formed = 98.1*(4+5) L
= 98.1*9 L = 882.9 L
