Answer :

To solve the division problem of 218 divided by 6, follow these steps for long division:

1. Set Up the Division:
- Write 218 inside the division bracket (the dividend), and 6 outside (the divisor).

2. Identify How Many Times 6 Fits into the First Few Digits of 218:
- Look at the first digit, which is 2. Since 6 cannot go into 2, consider the first two digits, which are 21.

3. Divide 21 by 6:
- Determine how many times 6 can go into 21 without exceeding it.
- 6 times 3 is 18, and 6 times 4 is 24. Since 24 is too much, use 6 times 3.
- Write 3 above the division bar.

4. Multiply and Subtract:
- Multiply 3 (the quotient) by 6 (the divisor), which gives 18.
- Subtract 18 from 21, which leaves a remainder of 3.

5. Bring Down the Next Digit:
- Bring down the next digit of the dividend, which is 8, making it 38.

6. Divide 38 by 6:
- Determine how many times 6 fits into 38.
- 6 times 6 is 36, and 6 times 7 is 42. Since 42 is too large, use 6 times 6.
- Write 6 above the division bar next to the 3.

7. Multiply and Subtract Again:
- Multiply 6 (the second quotient) by 6 (the divisor), which equals 36.
- Subtract 36 from 38, leaving a remainder of 2.

8. Conclusion:
- The quotient is 36, and the remainder is 2.

Thus, when 218 is divided by 6, the quotient is 36 and the remainder is 2.