Answer :
Sure! Let's break down the problem step-by-step to find the maximum number of palettes of roofing material that the elevator can carry in one trip:
1. Determine the Maximum Weight Capacity of the Elevator:
The elevator can carry a total weight of 2,320 pounds.
2. Account for the Weight of the Operator:
The operator weighs 195 pounds. Since the operator is already inside the elevator, we need to subtract this weight from the elevator's total capacity to find out how much more weight can be carried.
[tex]\[
\text{Available weight for palettes} = 2,320 \, \text{pounds} - 195 \, \text{pounds} = 2,125 \, \text{pounds}
\][/tex]
3. Determine the Weight of Each Palette:
Each palette of roofing material weighs 425 pounds.
4. Calculate the Maximum Number of Palettes:
To find out how many palettes the elevator can carry without exceeding the weight limit, divide the available weight by the weight of one palette.
[tex]\[
\text{Maximum number of palettes} = \frac{2,125 \, \text{pounds}}{425 \, \text{pounds per palette}} = 5
\][/tex]
Since we can't carry a fraction of a palette, we take the whole number result, which is 5.
Therefore, the maximum number of palettes of roofing material that the elevator can carry in one trip is 5.
1. Determine the Maximum Weight Capacity of the Elevator:
The elevator can carry a total weight of 2,320 pounds.
2. Account for the Weight of the Operator:
The operator weighs 195 pounds. Since the operator is already inside the elevator, we need to subtract this weight from the elevator's total capacity to find out how much more weight can be carried.
[tex]\[
\text{Available weight for palettes} = 2,320 \, \text{pounds} - 195 \, \text{pounds} = 2,125 \, \text{pounds}
\][/tex]
3. Determine the Weight of Each Palette:
Each palette of roofing material weighs 425 pounds.
4. Calculate the Maximum Number of Palettes:
To find out how many palettes the elevator can carry without exceeding the weight limit, divide the available weight by the weight of one palette.
[tex]\[
\text{Maximum number of palettes} = \frac{2,125 \, \text{pounds}}{425 \, \text{pounds per palette}} = 5
\][/tex]
Since we can't carry a fraction of a palette, we take the whole number result, which is 5.
Therefore, the maximum number of palettes of roofing material that the elevator can carry in one trip is 5.
