Answer :
Certainly! Let's solve the division problem [tex]\( 141 \div 50 \)[/tex] step-by-step to find the quotient and the remainder.
1. Set up the division:
- We have the dividend, which is 141, and the divisor, which is 50.
2. Determine how many times 50 fits into 141:
- First, see how many times 50 can go into the first two digits of 141, which are "14". Since 50 is greater than 14, it does not fit at all.
- Next, consider the whole number 141.
- Estimate how many times 50 fits into 141: We know that [tex]\( 50 \times 2 = 100 \)[/tex] and [tex]\( 50 \times 3 = 150 \)[/tex]. Since 150 is more than 141, 50 goes into 141 only 2 times.
3. Calculate the quotient:
- The quotient is the number of times 50 fits into 141, which is 2.
4. Calculate the remainder:
- Multiply the quotient back by the divisor: [tex]\( 2 \times 50 = 100 \)[/tex].
- Subtract this result from the dividend to find the remainder: [tex]\( 141 - 100 = 41 \)[/tex].
Therefore, when you divide 141 by 50, you get a quotient of 2 and a remainder of 41.
1. Set up the division:
- We have the dividend, which is 141, and the divisor, which is 50.
2. Determine how many times 50 fits into 141:
- First, see how many times 50 can go into the first two digits of 141, which are "14". Since 50 is greater than 14, it does not fit at all.
- Next, consider the whole number 141.
- Estimate how many times 50 fits into 141: We know that [tex]\( 50 \times 2 = 100 \)[/tex] and [tex]\( 50 \times 3 = 150 \)[/tex]. Since 150 is more than 141, 50 goes into 141 only 2 times.
3. Calculate the quotient:
- The quotient is the number of times 50 fits into 141, which is 2.
4. Calculate the remainder:
- Multiply the quotient back by the divisor: [tex]\( 2 \times 50 = 100 \)[/tex].
- Subtract this result from the dividend to find the remainder: [tex]\( 141 - 100 = 41 \)[/tex].
Therefore, when you divide 141 by 50, you get a quotient of 2 and a remainder of 41.
