Answer :
Sure! Let's find the empirical formula step by step for both parts (a) and (b).
### Part (a):
We have 39.3% Sodium (Na) and 60.7% Chlorine (Cl).
1. Find the moles of each element:
- Sodium (Na):
- Percentage by mass: 39.3%
- Molar mass of Na: 22.99 g/mol
- Moles of Na = [tex]\( \frac{39.3}{22.99} \)[/tex]
- Chlorine (Cl):
- Percentage by mass: 60.7%
- Molar mass of Cl: 35.45 g/mol
- Moles of Cl = [tex]\( \frac{60.7}{35.45} \)[/tex]
2. Calculate the mole ratio:
- Divide the moles of each element by the smallest number of moles calculated above.
3. Find the simplest whole number ratio:
- Sodium to Chlorine ratio becomes approximately 1:1.
Thus, the empirical formula for part (a) is NaCl.
### Part (b):
We have 56.5% Potassium (K), 8.7% Carbon (C), and 34.8% Oxygen (O).
1. Find the moles of each element:
- Potassium (K):
- Percentage by mass: 56.5%
- Molar mass of K: 39.10 g/mol
- Moles of K = [tex]\( \frac{56.5}{39.10} \)[/tex]
- Carbon (C):
- Percentage by mass: 8.7%
- Molar mass of C: 12.01 g/mol
- Moles of C = [tex]\( \frac{8.7}{12.01} \)[/tex]
- Oxygen (O):
- Percentage by mass: 34.8%
- Molar mass of O: 16.00 g/mol
- Moles of O = [tex]\( \frac{34.8}{16.00} \)[/tex]
2. Calculate the mole ratio:
- Divide the moles of each element by the smallest number of moles calculated above.
3. Find the simplest whole number ratio:
- Potassium to Carbon to Oxygen ratio is approximately 2:1:3.
Therefore, the empirical formula for part (b) is [tex]\( \text{K}_2\text{CO}_3 \)[/tex].
These are the empirical formulas based on the given composition data.
### Part (a):
We have 39.3% Sodium (Na) and 60.7% Chlorine (Cl).
1. Find the moles of each element:
- Sodium (Na):
- Percentage by mass: 39.3%
- Molar mass of Na: 22.99 g/mol
- Moles of Na = [tex]\( \frac{39.3}{22.99} \)[/tex]
- Chlorine (Cl):
- Percentage by mass: 60.7%
- Molar mass of Cl: 35.45 g/mol
- Moles of Cl = [tex]\( \frac{60.7}{35.45} \)[/tex]
2. Calculate the mole ratio:
- Divide the moles of each element by the smallest number of moles calculated above.
3. Find the simplest whole number ratio:
- Sodium to Chlorine ratio becomes approximately 1:1.
Thus, the empirical formula for part (a) is NaCl.
### Part (b):
We have 56.5% Potassium (K), 8.7% Carbon (C), and 34.8% Oxygen (O).
1. Find the moles of each element:
- Potassium (K):
- Percentage by mass: 56.5%
- Molar mass of K: 39.10 g/mol
- Moles of K = [tex]\( \frac{56.5}{39.10} \)[/tex]
- Carbon (C):
- Percentage by mass: 8.7%
- Molar mass of C: 12.01 g/mol
- Moles of C = [tex]\( \frac{8.7}{12.01} \)[/tex]
- Oxygen (O):
- Percentage by mass: 34.8%
- Molar mass of O: 16.00 g/mol
- Moles of O = [tex]\( \frac{34.8}{16.00} \)[/tex]
2. Calculate the mole ratio:
- Divide the moles of each element by the smallest number of moles calculated above.
3. Find the simplest whole number ratio:
- Potassium to Carbon to Oxygen ratio is approximately 2:1:3.
Therefore, the empirical formula for part (b) is [tex]\( \text{K}_2\text{CO}_3 \)[/tex].
These are the empirical formulas based on the given composition data.
