Answer :
To find the mass of 0.800 moles of Magnesium nitrate ([tex]\( \text{Mg(NO}_3\text{)}_2 \)[/tex]), you need to use its molar mass. The molar mass of Magnesium nitrate is given as 148.32 g/mol.
Here's how you can calculate the mass step-by-step:
1. Identify the number of moles: You have 0.800 moles of Magnesium nitrate.
2. Use the molar mass: The molar mass of Magnesium nitrate is 148.32 g/mol.
3. Calculate the mass: Multiply the number of moles by the molar mass to find the mass in grams:
[tex]\[
\text{Mass} = \text{Moles} \times \text{Molar mass} = 0.800 \, \text{moles} \times 148.32 \, \text{g/mol}
\][/tex]
4. Compute the result: Performing this calculation gives you a result of 118.656 grams.
Therefore, the closest choice to 118.656 g from the given options is 119 g. So, the mass of 0.800 moles of Magnesium nitrate is approximately 119 g.
Here's how you can calculate the mass step-by-step:
1. Identify the number of moles: You have 0.800 moles of Magnesium nitrate.
2. Use the molar mass: The molar mass of Magnesium nitrate is 148.32 g/mol.
3. Calculate the mass: Multiply the number of moles by the molar mass to find the mass in grams:
[tex]\[
\text{Mass} = \text{Moles} \times \text{Molar mass} = 0.800 \, \text{moles} \times 148.32 \, \text{g/mol}
\][/tex]
4. Compute the result: Performing this calculation gives you a result of 118.656 grams.
Therefore, the closest choice to 118.656 g from the given options is 119 g. So, the mass of 0.800 moles of Magnesium nitrate is approximately 119 g.
