High School

three times Andy's age is eleven more than twice belinda's age. the sum of their ages is two less than twice belinda's age. how old is each person

Answer :

a=andy's age
b=belinda's age



3a=11+2b

a+b=-2+2b

wowie

a+b=-2+2b
minus b from both sides
a=b-2

subsitute b-2 for a

3a=11+2b
3(b-2)=11+2b
3b-6=11+2b
minus 2b from both sides
b-6=11
add 6 to both sides
b=17

subsitute

a=b-2
a=17-2
a=15
andy is 15
belinda is 17

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