High School

A number, [tex]n[/tex], is added to 15 less than 3 times itself. The result is 101. Which equation can be used to find the value of [tex]n[/tex]?

A. [tex]3n - 15 + n = 101[/tex]

B. [tex]3n + 15 + n = 101[/tex]

C. [tex]3n - 15 - n = 101[/tex]

D. [tex]3n + 15 - n = 101[/tex]

Answer :

Sure! Let's solve the problem step-by-step.

### Problem Statement
A number [tex]\( n \)[/tex] is added to 15 less than 3 times itself. The result is 101. We need to find which equation can be used to determine the value of [tex]\( n \)[/tex].

### Step-by-Step Solution

1. Understand the Problem:
- We are given a number [tex]\( n \)[/tex].
- We need to add [tex]\( n \)[/tex] to a value which is 15 less than 3 times [tex]\( n \)[/tex].
- The equation then needs to equal 101.

2. Translate the Statement into an Equation:
- "A number [tex]\( n \)[/tex] is added to 15 less than 3 times itself":
- Three times [tex]\( n \)[/tex] is written as [tex]\( 3n \)[/tex].
- 15 less than 3 times [tex]\( n \)[/tex] is written as [tex]\( 3n - 15 \)[/tex].

- Adding [tex]\( n \)[/tex] to [tex]\( 3n - 15 \)[/tex]:
[tex]\[
n + (3n - 15)
\][/tex]

3. Formulate the Equation:
- The resultant value is given as 101:
[tex]\[
n + (3n - 15) = 101
\][/tex]

4. Simplify the Equation:
- Combine like terms:
[tex]\[
n + 3n - 15 = 101
\][/tex]
[tex]\[
4n - 15 = 101
\][/tex]

5. Solve for [tex]\( n \)[/tex]:
- Add 15 to both sides:
[tex]\[
4n = 116
\][/tex]

- Divide both sides by 4:
[tex]\[
n = 116 / 4
\][/tex]
[tex]\[
n = 29
\][/tex]

### Conclusion
The equation that represents the given problem is:
[tex]\[
3n - 15 + n = 101
\][/tex]
And the value of [tex]\( n \)[/tex] is:
[tex]\[
n = 29
\][/tex]

So, the correct equation that can be used to find [tex]\( n \)[/tex] is:
[tex]\[
3n - 15 + n = 101
\][/tex]

This corresponds to the first option in the given choices:
[tex]\[
\boxed{3n - 15 + n = 101}
\][/tex]