High School

A box m−83 kg is being pulled by a constant force F−141 N at an angle of θ -26 degrees. The initial speed of the box is zero.

Answer :

Final answer:

In this physics question, a box is being pulled with a constant force at an angle. We can find the acceleration of the box using Newton's second law and trigonometry. The box will start moving in the direction of the applied force with a specific acceleration.

Explanation:

In this question, we are given a box of mass 83 kg being pulled by a constant force of 141 N at an angle of 26 degrees. The initial speed of the box is zero. To analyze this situation, we can use Newton's second law, which states that force is equal to mass times acceleration. We can break down the force into its horizontal and vertical components to determine the acceleration of the box.

To find the horizontal component of the force, we can use trigonometry. The horizontal component is F_cos(theta), which in this case would be 141 N * cos(26 degrees) = 129.62 N. Since the initial speed is zero, we can assume that the box is at rest and the net force acting on it is equal to the force of friction. Therefore, the acceleration of the box is the net force divided by the mass, which is 129.62 N divided by 83 kg, resulting in approximately 1.562 m/s^2.

This means that the box will start moving in the direction of the applied force with an acceleration of 1.562 m/s^2.

Learn more about Newton's second law here:

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