Answer :
Sure! Let's determine the number of protons, neutrons, and electrons in the ion [tex]\({ }^{204} Pb^{4+}\)[/tex].
1. Determine the number of protons:
- The atomic number of Lead (Pb) is 82, meaning it has 82 protons.
2. Determine the number of neutrons:
- The mass number (given as 204) represents the total number of protons and neutrons in the nucleus.
- To find the number of neutrons:
[tex]\[
\text{Number of neutrons} = \text{Mass number} - \text{Number of protons}
\][/tex]
[tex]\[
\text{Number of neutrons} = 204 - 82 = 122
\][/tex]
3. Determine the number of electrons:
- Normally, an atom of lead would have the same number of electrons as protons, which is 82.
- However, since it is an ion with a [tex]\(4+\)[/tex] charge, it has lost 4 electrons.
- To find the number of electrons:
[tex]\[
\text{Number of electrons} = \text{Number of protons} - \text{Charge}
\][/tex]
[tex]\[
\text{Number of electrons} = 82 - 4 = 78
\][/tex]
Based on these calculations, the number of protons, neutrons, and electrons in [tex]\({ }^{204} Pb^{4+}\)[/tex] are:
- Protons: 82
- Neutrons: 122
- Electrons: 78
So, the correct answer is:
D. [tex]\(82, 122, 78\)[/tex]
1. Determine the number of protons:
- The atomic number of Lead (Pb) is 82, meaning it has 82 protons.
2. Determine the number of neutrons:
- The mass number (given as 204) represents the total number of protons and neutrons in the nucleus.
- To find the number of neutrons:
[tex]\[
\text{Number of neutrons} = \text{Mass number} - \text{Number of protons}
\][/tex]
[tex]\[
\text{Number of neutrons} = 204 - 82 = 122
\][/tex]
3. Determine the number of electrons:
- Normally, an atom of lead would have the same number of electrons as protons, which is 82.
- However, since it is an ion with a [tex]\(4+\)[/tex] charge, it has lost 4 electrons.
- To find the number of electrons:
[tex]\[
\text{Number of electrons} = \text{Number of protons} - \text{Charge}
\][/tex]
[tex]\[
\text{Number of electrons} = 82 - 4 = 78
\][/tex]
Based on these calculations, the number of protons, neutrons, and electrons in [tex]\({ }^{204} Pb^{4+}\)[/tex] are:
- Protons: 82
- Neutrons: 122
- Electrons: 78
So, the correct answer is:
D. [tex]\(82, 122, 78\)[/tex]
