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Find the probability of [tex]z[/tex] occurring in the indicated region of the standard normal distribution.

A normal curve is over a horizontal axis and is centered on 0. Vertical line segments extend from the horizontal axis to the curve at 0 and 1.69, where 1.69 is to the right of 0. The area under the curve between 0 and 1.69 is shaded.

\[ P(0 < z < 1.69) = \ \text{(Round to four decimal places as needed.)} \]

Answer :

The calculated value of the probability P(0 < z < 1.69) is 0.4545

To find the probability of z occurring in the indicated region of the standard normal distribution, we need to find the area under the standard normal curve between z = 0 and z = 1.69

From the standard normal table, the probability P(0 < z < 1.69) corresponds to the area under the curve between z = 0 \) and z = 1.69

Using the standard normal distribution, we have

P(0 < z < 1.69) = 0.4545

Hence, the probability P(0 < z < 1.69) is 0.4545

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