College

Solve application problems using single-variable linear inequalities.

The formula [tex]F = \frac{9}{5}C + 32[/tex] may be used to convert Celsius temperatures to Fahrenheit temperatures. What is the range of Celsius temperatures if the Fahrenheit range is [tex]-21^{\circ}F[/tex] to [tex]116^{\circ}F[/tex]?

The corresponding Celsius range would be [tex]\square[/tex] degrees to [tex]\square[/tex] degrees. Round Celsius temperature answers to 2 decimal places.

Answer :

To solve this problem, we need to find the range of Celsius temperatures when the Fahrenheit temperatures range from [tex]\(-21^\circ F\)[/tex] to [tex]\(116^\circ F\)[/tex]. We'll use the formula that converts Fahrenheit to Celsius:

[tex]\[ C = \frac{5}{9} (F - 32) \][/tex]

Step 1: Convert the lower Fahrenheit temperature to Celsius

1. Start with the lower bound of the Fahrenheit range: [tex]\(-21^\circ F\)[/tex].
2. Substitute [tex]\(-21^\circ F\)[/tex] into the conversion formula:
[tex]\[
C = \frac{5}{9} (-21 - 32)
\][/tex]
3. Simplify the expression inside the parentheses: [tex]\(-21 - 32 = -53\)[/tex].
4. Multiply:
[tex]\[
C = \frac{5}{9} \times (-53) = \frac{-265}{9} \approx -29.44
\][/tex]
5. Round to two decimal places: [tex]\(-29.44^\circ C\)[/tex].

Step 2: Convert the upper Fahrenheit temperature to Celsius

1. Now, take the upper bound of the Fahrenheit range: [tex]\(116^\circ F\)[/tex].
2. Substitute [tex]\(116^\circ F\)[/tex] into the conversion formula:
[tex]\[
C = \frac{5}{9} (116 - 32)
\][/tex]
3. Simplify the expression inside the parentheses: [tex]\(116 - 32 = 84\)[/tex].
4. Multiply:
[tex]\[
C = \frac{5}{9} \times 84 = \frac{420}{9} \approx 46.67
\][/tex]
5. Round to two decimal places: [tex]\(46.67^\circ C\)[/tex].

Final Answer

The corresponding Celsius range for Fahrenheit temperatures between [tex]\(-21^\circ F\)[/tex] and [tex]\(116^\circ F\)[/tex] is approximately [tex]\(-29.44^\circ C\)[/tex] to [tex]\(46.67^\circ C\)[/tex].

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