Answer :
The force of kinetic friction is 147 N. Thus the correct answer is option (2).
To calculate the force of kinetic friction, we utilize the formula [tex]\(f_k = \mu_k \times N\)[/tex], where [tex]\(f_k\)[/tex] is the force of kinetic friction, [tex]\(\mu_k\)[/tex] is the coefficient of kinetic friction, and (N) is the normal force. Firstly, we find the normal force acting on the box, which equals the weight of the box since it's on a horizontal surface. The weight is given by the formula [tex]\(W = m \times g\)[/tex], where (m) is the mass and (g) is the acceleration due to gravity. So, [tex]\(W = 50 \, kg \times 9.8 \, m/s^2 = 490 \, N\).[/tex]
Next, we calculate the force of kinetic friction using the provided coefficient of kinetic friction [tex]\(\mu_k = 0.3\)[/tex]. Therefore, [tex]\(f_k = 0.3 \times 490 \, N = 147 \, N\)[/tex].
Therefore, the correct answer is option (2).
