Answer :
Final answer:
The question asks for the Celsius temperature at which an ideal gas of a specified volume, number of moles, and pressure will occupy. This can be found by using the ideal gas law equation and converting the obtained Kelvin temperature to Celsius.
Explanation:
To answer the question 'At what Celsius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa?', we will employ the ideal gas law, which is formulated as PV = nRT. In this formula, P is the pressure (in this case, 114 kPa), V is the volume (35.9 L), n is the number of moles (0.750 mol), R is the constant (8.31 J/(mol·K) in the SI system), and T is the temperature. To obtain the temperature in Kelvin, we rearrange the equation bringing PV/nR to one side, equating it to T.
Plugging in the given values:
114 kPa * 35.9 L / (0.750 mol * 8.314 J/(mol·K)) = T
Converting this further to Celsius by subtracting 273.15 from the Kelvin result.
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Answer:
The temperature in Celsius is 383, 7°C
Explanation:
We use the formula PV=nRT. We convert the pressure in KPa into atm:
101,325kPa---1 atm
114kPa--------x=(114kPa x 1 atm)/101,325kPa=1, 125 atm
PV=nRT ---> T= PV/nR
T=1, 125 atm x 35, 9 L/ 0,750 mol x 0,082 l atm/K mol
T= 656, 7 K
0°C= 273K---> 656,7 -273K= 383,7°C
