Answer :
For 2.4 moles of NaHCO3 with a molar mass of 84.01 g/mol, the resulting mass is 201.624 grams. For 1.8 moles of potassium (K) with a molar mass of 39.1 g/mol, the mass is 70.38 grams. 201.624 grams of NaHCO3 and 70.38 grams of K.
To calculate the mass of NaHCO3 (sodium hydrogen carbonate) when you have 2.4 moles, you multiply the number of moles by the molar mass of NaHCO3. The molar mass of NaHCO3 is 84.01 g/mol. So, the total mass is 2.4 moles imes 84.01 g/mol = 201.624 grams of NaHCO3.
For the element potassium (K), with a molar mass of 39.1 g/mol and having 1.8 moles, you do a similar calculation: 1.8 moles imes 39.1 g/mol = 70.38 grams of K.
