Answer :
Final answer:
The calculated stopping force that acts on a 30kg object dropped from 5m and sinking 0.1m into the clay is 14700 N, which does not match any of the given options.
Explanation:
To calculate the force that stops the object as it sinks into the soft clay, we use the work-energy principle. The work done by the stoping force can be represented as the product of the force (F) and the distance over which it acts (0.1 m). This work is equal to the initial gravitational potential energy (mgh) that the object had before sinking into the clay.
The gravitational potential energy is calculated using the mass (m = 30kg), the gravitational acceleration (g = 9.8 m/s²), and the height (h = 5m).
Ep = mgh
Ep = 30kg × 9.8 m/s² × 5m
Ep = 1470 J (joules)
The work done by the force to stop the object is:
Work = Force x Distance
1470 J = F × 0.1 m
F = 1470 J / 0.1 m
F = 14700 N
Therefore, none of the provided options (a) 29.4 N, (b) 49.0 N, (c) 98.1 N, (d) 19.6 N match the calculated force. The correct answer is not stated among the options; the calculated force is 14700 N.
