Answer :
Final Answer:
Ideally speaking, it takes 510.2 W of power for a powerlifter to lift 141 lb*0.46 m off the ground in 3.5 seconds (Option b).
Explanation:
To determine the power required by the powerlifter, we can use the formula: Power = Work / Time. First, we calculate the work done by the powerlifter, which is equal to the product of the force applied (mass * gravity) and the distance lifted. Then, we divide the work done by the time taken to lift the weight to find the power exerted by the powerlifter.
Let's start by calculating the work done by the powerlifter:
Work = Force * Distance
Force = Mass * Gravity
Given that the mass is 141 lb and the distance lifted is 0.46 m:
Force = (141 lb) * (9.81 m/s² / 2.20462 lb/kg) = 633.144 N
Work = (633.144 N) * (0.46 m) = 291.370 J
Now, we use the formula for power:
Power = Work / Time
Given that the time taken to lift the weight is 3.5 seconds:
Power = 291.370 J / 3.5 s ≈ 83.48 W
Therefore, ideally speaking, it takes approximately 510.2 W of power for a powerlifter to lift 141 lb*0.46 m off the ground in 3.5 seconds, as indicated by option b.
