Answer :
Final answer:
Using Hooke's Law, the force required to compress the spring with a spring constant of 444 N/m by 8.8 cm is calculated to be 39.1 N. Therefore, option c) 39.1 N, is the correct answer.
Explanation:
To determine the force needed to compress the spring by 8.8 cm against a wall, we can use Hooke's Law, which states that the force F needed to compress or stretch a spring by a displacement x is directly proportional to both the displacement and the spring constant k: F = kx. In this case, the spring constant k is given as 444 N/m. Since 1 cm is equivalent to 0.01 m, we need to convert the displacement from centimeters to meters before applying the formula. Therefore, 8.8 cm is equivalent to 0.088 m. Applying Hooke's Law:
F = kx = 444 N/m * 0.088 m = 39.1 N
Therefore, the force required to hold the spring squished by 8.8 cm is 39.1 N.
