Answer :
The density of titanium in this block is 4.51 g/cm³.
Here's how to calculate the density of titanium in g/cm³:
**1. Convert all dimensions to the same unit (cm):**
* Width (w) = 15.0 mm * (1 cm / 10 mm) = 1.50 cm
* Height (h) = 1.00 dm * (10 cm / 1 dm) = 10.0 cm
**2. Calculate the volume (V) of the block:**
V = length (l) * width (w) * height (h)
V = 25.0 cm * 1.50 cm * 10.0 cm = 375 cm³
**3. Convert the mass (m) to grams:**
m = 1.69 kg * (1000 g / 1 kg) = 1690 g
**4. Calculate the density (ρ):**
ρ = m / V
ρ = 1690 g / 375 cm³ = 4.51 g/cm³
Therefore, the density of titanium in this block is 4.51 g/cm³.
The probable question may be:
A block of titanium of dimensions of 25.0 cm × 15.0 mm×1.00 dm has a mass of 1.69 kg. How do you calculate the density of titanium in g/cm³?
