Answer :
Given:
• Amount of fat stored = 3500 Cal
,• Average rate of fat burned = 0.45 Cal/h
,• Weight of person = 122 lb
,• Time = 7 hours
Let's find the number of calories the person will burn.
Since the average rate an adult burns is 0.45 Cal/h for every pound, it means the amount the person will burn per hour is:
A = 0.45 x 122 = 54.9 Cal/h
Now, the person slept for a total of 7 hours.
The total amount the person will burn for 7 hours will be:
54.9 x 7 = 384.3 Cal.
Therefore, the amount of calories the person will burn is 384.3 Cal.
ANSWER:
384.3 Cal.
Final answer:
A 122 lb person would burn approximately 38.61 Calories during 7 hours of sleep, calculated by multiplying the Calories burned per hour per pound by the person's weight and the number of hours slept.
Explanation:
To calculate how many Calories a 122 lb person burns during 7 hours of sleep, we can use the given burn rate of 0.45 Cal/h per pound of body weight. We perform the following calculation:
Total Calories burned = (Calories burned per hour per pound) x (body weight in pounds) x (number of hours of sleep)
Total Calories burned = 0.45 Cal/h/lb x 122 lbs x 7 h = 38.61 Cal
Therefore, a 122 lb person would burn approximately 38.61 Calories during 7 hours of sleep.
