High School

Jet engines on the 100 mg VTOL (vertical take-off and landing) aircraft exert a constant vertical force of 981 kN as it hovers. Determine the net impulse on the aircraft over [tex] t = 10 \, s [/tex].

A. 9.81 kNs

B. 98.1 kNs

C. 981 kNs

D. 9.81 Ns

Answer :

Final answer:

The net impulse on a VTOL aircraft exerting a vertical force of 981 kN over 10 seconds is calculated by multiplying force by time, resulting in an impulse of 981 kNs. The correct option is c.

Explanation:

The question involves calculating the net impulse exerted on a VTOL aircraft during hover over a certain time period. The impulse of a force is the product of the force and the time period over which it acts. The formula to determine impulse (I) is given by:

I = Force (F) × Time (t)

Given that the vertical force exerted by the jet engines is 981 kN and it acts over a time interval of 10 seconds, we can calculate the impulse as follows:

I = 981 kN × 10 s

It is important to ensure that the units are consistent when performing the calculation. Here, we have kN (kilonewtons) for force and seconds for time, which gives us the impulse in kiloNewton-seconds (kNs). So, the impulse would be:

I = 9810 kNs

This is equivalent to 9810 kNs, or 9810×103 N×s, which is equal to 9810 Ns after converting kilonewtons to newtons by multiplying by 1000. Therefore, the correct answer is C) 981 kNs.