Answer :
Final answer:
To find the mass of Co(NO3)3 in a 1.69 L, 0.452 M solution, calculate the moles using molarity and volume, then multiply by the molar mass of Co(NO3)3 to get 222.23 grams.
Explanation:
The question asks, What mass, in grams, of Co(NO3)3 is present in 1.69 L of a 0.452 M solution? To solve this, we will first use the formula for molarity, which is moles of solute over liters of solution (M = moles/L). Given the molarity (M) is 0.452 and the volume of the solution is 1.69 L, we can calculate the number of moles of Co(NO3)3 present.
Step 1: Calculate moles of Co(NO3)3 = Molarity (M) × Volume (L) = 0.452 M × 1.69 L = 0.7638 moles.
Step 2: To find the mass of these moles, we multiply by the molar mass of Co(NO3)3, which is 291.03 g/mol (calculated from the atomic masses of Co, N, and O).
Step 3: Mass = Moles × Molar mass = 0.7638 moles × 291.03 g/mol = 222.23 grams of Co(NO3)3.
Therefore, the mass of Co(NO3)3 present in 1.69 L of a 0.452 M solution is 222.23 grams.
