Answer :
If you gave me just one piece of information which is how old you were in 2000 then i would have perfectly answered your question. I am heart-fully sorry
Final answer:
William was 3 years old in January 2000. We created algebraic equations based on the information given for the years 2000 and 2009 and solved for William's age.
Explanation:
To solve how old William was in January of the year 2000, using the information provided, we will set up two algebraic equations to represent the two scenarios. Let's denote William's age in January 2000 as w, and the student's age as s.
The first statement can be translated to an equation as follows: In January 2000, the student was one more than eleven times as old as William. This gives us the equation s = 11w + 1.
The second statement tells us that in January 2009, the student was seven more than three times as old as William. Since 9 years have passed for both the student and William, we need to account for this in our second equation: s + 9 = 3(w + 9) + 7.
Replacing s from the first equation into the second, we get: 11w + 1 + 9 = 3(w + 9) + 7. Simplifying this gives us the equation: 11w + 10 = 3w + 34. This simplifies to 8w = 24, and by dividing both sides by 8, we obtain w = 3.
Therefore, William was 3 years old in January of the year 2000.
