Answer :
Final answer:
Using Hooke's Law, the maximum force on a 0.217 kg mass attached to a spring with a constant of 122 N/m and compressed 0.166 m is found to be 20.252 N.
Explanation:
To find the maximum force on the mass when a 0.217 kg mass is attached to a spring with a spring constant of 122 N/m and released from rest when the spring is compressed 0.166 m, we can use Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to its displacement from the equilibrium position, which is given by the formula F = kx, where F is the force in Newtons (N), k is the spring constant in N/m, and x is the displacement in meters (m).
Substituting the given values:
- k = 122 N/m
- x = 0.166 m
The maximum force, F, on the mass is:
F = 122 N/m * 0.166 m = 20.252 N
Therefore, the maximum force on the mass is 20.252 N.
