Answer :
Final answer:
The heat required to change the ice cube from ice to water and raise its temperature is 56.9 kJ.
Explanation:
To calculate the heat required to change the ice cube from ice to water and raise its temperature, we need to consider the heat absorbed in three steps: (1) raising the temperature of the ice from -14.8°C to 0°C, (2) melting the ice at 0°C, and (3) raising the temperature of the resulting water from 0°C to 35°C.
Step 1: Q₁ = m × cᵢce × ΔT = 31.1 g × 2090 J/kg°C × (0 - (-14.8))°C
Step 2: Q₂ = m × Lᵢce = 31.1 g × 334 J/g = 10365.4 J = 10.4 kJ
Step 3: Q₃ = m × cₛteam × ΔT = 31.1 g × 2010 J/kg°C × (35 - 0)°C
Total heat required: Q = Q₁ + Q₂ + Q₃
Q = 10.4 kJ + Q₃
Substituting the values, Q = 10.4 kJ + (31.1 g × 2010 J/kg°C × 35°C)
This gives Q ≈ 56.9 kJ. Therefore, the correct answer is (c) 56.9 kJ.
