High School

As weighed, the total empty weight of an aircraft is 5,862 pounds with a moment of 885,957. However, when the aircraft was weighed, 20 pounds of potable water were on board at +84, and 23 pounds of hydraulic fluid were in a tank located at +101. What is the empty weight CG of the aircraft?

Answer :

Final answer:

To find the empty weight CG (Center of Gravity) of the aircraft, subtract the moments caused by the potable water and hydraulic fluid from the total moment. The empty weight CG is 881,954 lb-in.

Explanation:

To find the empty weight CG (Center of Gravity) of the aircraft, we need to calculate the moment caused by the potable water and hydraulic fluid, and then subtract it from the total moment. The moment caused by the potable water is calculated by multiplying its weight (20 pounds) with its moment arm (+84), and the moment caused by the hydraulic fluid is calculated by multiplying its weight (23 pounds) with its moment arm (+101). Then we can subtract the sum of these moments from the total moment to find the empty weight CG. The moment caused by the potable water is 20 pounds * +84 = 1,680 lb-in. The moment caused by the hydraulic fluid is 23 pounds * +101 = 2,323 lb-in. Total moment = 885,957 lb-in - (1,680 lb-in + 2,323 lb-in) = 881,954 lb-in. Therefore, the empty weight CG of the aircraft is 881,954 lb-in.

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