College

**Practice Exercise**

If 60.2 mL of 0.427 M KOH solution are required to neutralize 10.1 mL of H₂SO₄ solution, what is the concentration of the H₂SO₄ solution in molarity?

Answer :

Final answer:

To find the concentration of the H₂SO4 solution in molarity, use the formula M₁V₁ = M₂V₂ and solve for M₂.


Explanation:

To find the concentration of the H₂SO4 solution in molarity, we can use the formula:



M₁V₁ = M₂V₂



Where M₁ is the concentration of the KOH solution (0.427 M), V₁ is the volume of the KOH solution (60.2 mL), M₂ is the concentration of the H₂SO4 solution (unknown), and V₂ is the volume of the H₂SO4 solution (10.1 mL).



Substituting the known values into the equation, we have:



(0.427 M)(60.2 mL) = (M₂)(10.1 mL)



Solving for M₂, we get:



M₂ = (0.427)(60.2) / (10.1)



M₂ = 2.543 M



Therefore, the concentration of the H₂SO4 solution is 2.543 M.


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