Answer :
Final answer:
The problem can be solved by setting up the given information as an algebraic equation. The smaller integer in the pair of consecutive odd integers, as defined by the given conditions, is 13.
Explanation:
Let's define the two consecutive odd integers as x (the smaller integer) and x+2 (the next odd integer). According to the problem, if we double the smaller integer (2x), the result should be eleven more than the next odd integer. So, we can express this as an equation: 2x=(x+2) +11. Simplifying this gives 2x=x+13. Solving for x, we subtract 'x' from both sides which leaves us with x=13. Therefore, the smaller integer in the two consecutive odd integers is 13.
Learn more about Consecutive Odd Integers here:
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