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What is the mass of [tex]3.30 \times 10^{23}[/tex] atoms of silver (Ag)?

A. 197 g
B. 0.549 g
C. 25.8 g
D. 85.7 g
E. 59.1 g

Answer :

Final answer:

The mass of 3.30 x 10^23 atoms of silver (Ag) is 59.1 g.


Explanation:

The molar mass of silver (Ag) is 107.87 g/mol. To find the mass of 3.30 x 10^23 atoms of silver, you need to convert the number of atoms to moles using Avogadro's number.

Number of moles = Number of atoms / Avogadro's number

Mass = Number of moles x Molar mass

Plugging in the values,

Number of moles = 3.30 x 10^23 atoms / 6.022 x 10^23 atoms/mol = 0.547 mol

Mass = 0.547 mol x 107.87 g/mol = 59.1 g


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