Answer :
Final answer:
To calculate the number of grams of Ne contained in 36.2 L of Ne gas, we use the ideal gas law and molar volume of gas at STP. First, we find the number of moles in 36.2 L, then multiply it by the molar mass of Ne to get the mass in grams. The answer is approximately 32.7 g of Ne.
Explanation:
The question asks us to calculate the number of grams of Ne (Neon) contained in 36.2 L of Ne gas. To solve this, we need to use the ideal gas law and the molar volume of gas at standard temperature and pressure (STP).
At STP, 1 mole of any gas occupies about 22.4 L. So, first, we calculate the number of moles of Ne in 36.2 L using the relationship:
Number of moles = Volume of gas / Molar volume at STP
Number of moles of Ne = 36.2 L / 22.4 L/mol = approximately 1.62 moles
The molar mass of Ne (from the periodic table) is 20.18 g/mol. Let's then calculate the mass of Ne:
Mass of Ne = Number of moles x Molar mass
Mass of Ne = 1.62 moles x 20.18 g/mol = approximately 32.7 g of Ne
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