A 27 kg chair initially at rest on a horizontal floor requires a 173 N horizontal force to set it in motion. Once the chair is in motion, a 148 N horizontal force keeps it moving at a constant velocity.

What is the coefficient of static friction between the chair and the floor?

A. 0.4
B. 0.5
C. 0.6
D. 0.7

The coefficient of static friction between the chair and the floor can be calculated using the force required to initiate movement and the normal force. By substitifying the given values into the formula, the coefficient of static friction is found to be approximately 0.6.

Explanation:

The question asks for the coefficient of static friction between the chair and the floor. The coefficient of static friction can be calculated using the formula: fs = µs * N, where fs is the force of static friction (the force required to make the object start to move), µs is the coefficient of static friction, and N is the normal force (equal to the weight of the chair). We can rearrange the formula to find µs = fs/N.

Given in the problem are the values of fs = 173 N and the weight of the chair is 27 kg. The normal force N is the weight of the chair, which we can find by multiplying its mass by the gravity: N = m*g = 27 kg * 9.8 m/s² = 264.6 N.

Substituting these values into the rearranged formula gives us the coefficient of static friction as: µs = fs/N = 173 N / 264.6 N = 0.653. Therefore, the coefficient of static friction between the chair and the floor is closest to c) 0.6.

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