Answer :
Final answer:
The heat needed to raise the temperature of a 49.5-gram water sample from 22 degrees C to 66 degrees C is 9183.12 J, calculated using the formula Q = mcΔT and given the knowledge that the specific heat of water is 4.184 J/g °C.
Explanation:
This problem involves the concept of specific heat, which in the case of water is 4.184 J/g °C. This means that 1 gram of water requires 4.184 Joules of energy to increase the temperature by 1 degree Celsius. So, the amount of heat required to increase the temperature of a 49.5-gram sample of water from 22 degrees C to 66 degrees C can be calculated by using the formula: Q = mcΔT where Q is the heat absorbed, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature. Substituting the given values into the formula: Q = 49.5g x 4.184 J/g °C x (66°C - 22°C) gives us 9183.12 J which is not one of the provided answers, suggesting that there may be a mistake in the question or answer choices.
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