High School

The body temperatures in degrees Fahrenheit of a sample of adults in one small town are as follows:

98.6, 98.4, 98.8, 98.9, 98.2, 98.7, 98.3, 98.5, 98.6, 98.4, 98.2, 98.5, 98.9, 98.7, 98.6, 98.4, 98.8, 98.3, 98.5, 98.6.

Assume body temperatures of adults are normally distributed. Based on this data, find the 90% confidence interval for the mean body temperature.

A. (98.4, 98.8)
B. (98.2, 98.9)
C. (98.3, 98.7)
D. (98.2, 98.8)

Answer :

Final answer:

To find the 90% confidence interval for the mean body temperature, calculate the mean and standard deviation, find the critical value, and use the formula. The correct answer is (98.3, 98.7).

Explanation:

To find the 90% confidence interval for the mean body temperature, we can use the formula:

Confidence interval = mean ± (critical value)(standard deviation)

First, we need to calculate the mean and standard deviation of the body temperatures. Then, we can find the critical value for a 90% confidence level. Using these values, we can calculate the confidence interval.

After performing the calculations, the 90% confidence interval for the mean body temperature is (98.3, 98.7). Therefore, the correct answer is option (c) (98.3, 98.7).

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