High School

The quotient of [tex]\left(x^4+5x^3-3x-15\right)[/tex] and [tex]\left(x^3-3\right)[/tex] is a polynomial. What is the quotient?

A. [tex]x^7+5x^6-6x^4-30x^3+9x+45[/tex]
B. [tex]x-5[/tex]
C. [tex]x+5[/tex]
D. [tex]x^7+5x^6+6x^4+30x^3+9x+45[/tex]

Answer :

Let's solve the problem step-by-step by performing polynomial long division.

We need to divide the polynomial [tex]\(x^4 + 5x^3 - 3x - 15\)[/tex] by [tex]\(x^3 - 3\)[/tex].

### Step 1: Setup

Write the dividend [tex]\(x^4 + 5x^3 - 3x - 15\)[/tex] and the divisor [tex]\(x^3 - 3\)[/tex].

### Step 2: Divide the Leading Terms

Divide the leading term of the dividend [tex]\(x^4\)[/tex] by the leading term of the divisor [tex]\(x^3\)[/tex]:

[tex]\[
\frac{x^4}{x^3} = x
\][/tex]

### Step 3: Multiply and Subtract

Multiply the entire divisor [tex]\(x^3 - 3\)[/tex] by the result from Step 2 ([tex]\(x\)[/tex]):

[tex]\[
x(x^3 - 3) = x^4 - 3x
\][/tex]

Subtract this result from the original dividend:

[tex]\[
(x^4 + 5x^3 - 3x - 15) - (x^4 - 3x) = 5x^3 + 0x^2 - 15
\][/tex]

### Step 4: Repeat

Now repeat the process with the new polynomial [tex]\(5x^3 + 0x^2 - 15\)[/tex].

- Divide the leading term [tex]\(5x^3\)[/tex] by [tex]\(x^3\)[/tex]:

[tex]\[
\frac{5x^3}{x^3} = 5
\][/tex]

- Multiply the divisor by [tex]\(5\)[/tex]:

[tex]\[
5(x^3 - 3) = 5x^3 - 15
\][/tex]

- Subtract the result from [tex]\(5x^3 + 0x^2 - 15\)[/tex]:

[tex]\[
(5x^3 + 0x^2 - 15) - (5x^3 - 15) = 0x^2 + 0x
\][/tex]

Since we are left with a zero remainder, we stop here.

### Final Quotient

The quotient of the division is the terms we found during the division steps:

[tex]\[
x + 5
\][/tex]

So, the quotient of [tex]\(\left(x^4 + 5x^3 - 3x - 15\right)\)[/tex] and [tex]\(\left(x^3 - 3\right)\)[/tex] is [tex]\(x + 5\)[/tex].

Answer: [tex]\(x + 5\)[/tex]